問題文全文(内容文)：
①$1\displaystyle \frac{3}{5}+\displaystyle \frac{1}{4}=$
②$3\displaystyle \frac{3}{4}-1\displaystyle \frac{5}{12}=$
③$2\displaystyle \frac{2}{3}-2\displaystyle \frac{1}{6}=$
④$1\displaystyle \frac{4}{5}+\displaystyle \frac{7}{10}=$
⑤$3\displaystyle \frac{2}{5}-\displaystyle \frac{1}{2}=$
⑥$2\displaystyle \frac{3}{4}-\displaystyle \frac{7}{8}=$
①$1\displaystyle \frac{3}{5}+\displaystyle \frac{1}{4}=$
②$3\displaystyle \frac{3}{4}-1\displaystyle \frac{5}{12}=$
③$2\displaystyle \frac{2}{3}-2\displaystyle \frac{1}{6}=$
④$1\displaystyle \frac{4}{5}+\displaystyle \frac{7}{10}=$
⑤$3\displaystyle \frac{2}{5}-\displaystyle \frac{1}{2}=$
⑥$2\displaystyle \frac{3}{4}-\displaystyle \frac{7}{8}=$
単元：
#算数(中学受験)#計算と数の性質#いろいろな計算
指導講師：
とある男が授業をしてみた
問題文全文(内容文)：
①$1\displaystyle \frac{3}{5}+\displaystyle \frac{1}{4}=$
②$3\displaystyle \frac{3}{4}-1\displaystyle \frac{5}{12}=$
③$2\displaystyle \frac{2}{3}-2\displaystyle \frac{1}{6}=$
④$1\displaystyle \frac{4}{5}+\displaystyle \frac{7}{10}=$
⑤$3\displaystyle \frac{2}{5}-\displaystyle \frac{1}{2}=$
⑥$2\displaystyle \frac{3}{4}-\displaystyle \frac{7}{8}=$
①$1\displaystyle \frac{3}{5}+\displaystyle \frac{1}{4}=$
②$3\displaystyle \frac{3}{4}-1\displaystyle \frac{5}{12}=$
③$2\displaystyle \frac{2}{3}-2\displaystyle \frac{1}{6}=$
④$1\displaystyle \frac{4}{5}+\displaystyle \frac{7}{10}=$
⑤$3\displaystyle \frac{2}{5}-\displaystyle \frac{1}{2}=$
⑥$2\displaystyle \frac{3}{4}-\displaystyle \frac{7}{8}=$
投稿日：2013.11.10
