問題文全文(内容文)：
次の計算をしよう.
1.$\boxed{1}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5\\
3x+5y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{2}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
3x+y=12\\
x-y=8
\end{array}
\right.
\end{eqnarray}$
$\boxed{3}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
5x+2y=-1\\
-3x+y=5
\end{array}
\right.
\end{eqnarray}$
$\boxed{4}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-3y=5 \\
x-2y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{5}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
4x-9y=7 \\
5x-6y=7
\end{array}
\right.
\end{eqnarray}$
$\boxed{6}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-y=6\\
4x-3y=17
\end{array}
\right.
\end{eqnarray}$
次の計算をしよう.
1.$\boxed{1}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5\\
3x+5y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{2}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
3x+y=12\\
x-y=8
\end{array}
\right.
\end{eqnarray}$
$\boxed{3}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
5x+2y=-1\\
-3x+y=5
\end{array}
\right.
\end{eqnarray}$
$\boxed{4}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-3y=5 \\
x-2y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{5}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
4x-9y=7 \\
5x-6y=7
\end{array}
\right.
\end{eqnarray}$
$\boxed{6}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-y=6\\
4x-3y=17
\end{array}
\right.
\end{eqnarray}$
単元：
#数学(中学生)#中２数学#連立方程式
指導講師：
とある男が授業をしてみた
問題文全文(内容文)：
次の計算をしよう.
1.$\boxed{1}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5\\
3x+5y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{2}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
3x+y=12\\
x-y=8
\end{array}
\right.
\end{eqnarray}$
$\boxed{3}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
5x+2y=-1\\
-3x+y=5
\end{array}
\right.
\end{eqnarray}$
$\boxed{4}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-3y=5 \\
x-2y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{5}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
4x-9y=7 \\
5x-6y=7
\end{array}
\right.
\end{eqnarray}$
$\boxed{6}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-y=6\\
4x-3y=17
\end{array}
\right.
\end{eqnarray}$
次の計算をしよう.
1.$\boxed{1}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5\\
3x+5y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{2}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
3x+y=12\\
x-y=8
\end{array}
\right.
\end{eqnarray}$
$\boxed{3}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
5x+2y=-1\\
-3x+y=5
\end{array}
\right.
\end{eqnarray}$
$\boxed{4}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-3y=5 \\
x-2y=4
\end{array}
\right.
\end{eqnarray}$
$\boxed{5}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
4x-9y=7 \\
5x-6y=7
\end{array}
\right.
\end{eqnarray}$
$\boxed{6}$
$\begin{eqnarray}
\left\{
\begin{array}{l}
2x-y=6\\
4x-3y=17
\end{array}
\right.
\end{eqnarray}$
投稿日：2016.07.14
