問題文全文(内容文)：
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-5y=-2 \\
-x+2y=-1
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5 \\
2x+3y=-4
\end{array}
\right.
\end{eqnarray}$
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-5y=-2 \\
-x+2y=-1
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5 \\
2x+3y=-4
\end{array}
\right.
\end{eqnarray}$
単元：
#数学(中学生)#中２数学#連立方程式
指導講師：
3rd School
問題文全文(内容文)：
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-5y=-2 \\
-x+2y=-1
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5 \\
2x+3y=-4
\end{array}
\right.
\end{eqnarray}$
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-5y=-2 \\
-x+2y=-1
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
x-2y=5 \\
2x+3y=-4
\end{array}
\right.
\end{eqnarray}$
投稿日：2024.06.18
