問題文全文(内容文)：
中２ 数学　連立方程式（加減法）
次の連立方程式を解け
$\begin{cases}
3x+2y=4 \\
x-y=3
\end{cases}$

問題文全文(内容文)：
x,yについての連立方程式
$ \begin{eqnarray}
\left\{
\begin{array}{l}
\dfrac{3}{3x+4y}-\dfrac{4}{4x-3y}=10 \\
\dfrac{4}{3x+4y}+\dfrac{3}{4x-3y}=5
\end{array}
\right.
\end{eqnarray}$
を解け.

東大寺学園高校過去問

問題文全文(内容文)：
Let's enjoy oriental mathematics for just a little while.
You will discover a cute world from mathematics.
Everyone in the world should love and be good at mathematics.

We are introducing the entrance exam questions for Japanese high schools.
It's an important issue for you to understand the basics of mathematics.
Would you like to solve this math problem and check out our commentary?

問題文全文(内容文)：
連立方程式を解け
\begin{eqnarray}
\left\{
\begin{array}{l}
3x + 2y = 6 \\
6xy = 5
\end{array}
\right.
\end{eqnarray}

慶應義塾高等学校

問題文全文(内容文)：
$
\begin{eqnarray}
\left\{
\begin{array}{l}
x - 3y = 4 \\
x + 9y = -1
\end{array}
\right.
\end{eqnarray}
$
のとき
$\frac{x^2-27y^2}{3}+2xy$

京都女子高等学校