問題文全文(内容文)：
( )も分数も少数も全部消してやるぜ！
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
3(x+y)=4x-7 \\
2x=3y+8
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
0.5x-0.2y=2 \\
2x-3y=-3
\end{array}
\right.
\end{eqnarray}$
③
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{x}{3}=+\displaystyle \frac{y}{4}=-1 \\
3y=5x-9
\end{array}
\right.
\end{eqnarray}$
④
$\begin{eqnarray}
\left\{
\begin{array}{l}
2(3x+y)=8x+y+9 \\
5x-4y+30=0
\end{array}
\right.
\end{eqnarray}$
( )も分数も少数も全部消してやるぜ！
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
3(x+y)=4x-7 \\
2x=3y+8
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
0.5x-0.2y=2 \\
2x-3y=-3
\end{array}
\right.
\end{eqnarray}$
③
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{x}{3}=+\displaystyle \frac{y}{4}=-1 \\
3y=5x-9
\end{array}
\right.
\end{eqnarray}$
④
$\begin{eqnarray}
\left\{
\begin{array}{l}
2(3x+y)=8x+y+9 \\
5x-4y+30=0
\end{array}
\right.
\end{eqnarray}$
単元：
#数学(中学生)#中２数学#連立方程式
指導講師：
とある男が授業をしてみた
問題文全文(内容文)：
( )も分数も少数も全部消してやるぜ！
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
3(x+y)=4x-7 \\
2x=3y+8
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
0.5x-0.2y=2 \\
2x-3y=-3
\end{array}
\right.
\end{eqnarray}$
③
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{x}{3}=+\displaystyle \frac{y}{4}=-1 \\
3y=5x-9
\end{array}
\right.
\end{eqnarray}$
④
$\begin{eqnarray}
\left\{
\begin{array}{l}
2(3x+y)=8x+y+9 \\
5x-4y+30=0
\end{array}
\right.
\end{eqnarray}$
( )も分数も少数も全部消してやるぜ！
①
$\begin{eqnarray}
\left\{
\begin{array}{l}
3(x+y)=4x-7 \\
2x=3y+8
\end{array}
\right.
\end{eqnarray}$
②
$\begin{eqnarray}
\left\{
\begin{array}{l}
0.5x-0.2y=2 \\
2x-3y=-3
\end{array}
\right.
\end{eqnarray}$
③
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{x}{3}=+\displaystyle \frac{y}{4}=-1 \\
3y=5x-9
\end{array}
\right.
\end{eqnarray}$
④
$\begin{eqnarray}
\left\{
\begin{array}{l}
2(3x+y)=8x+y+9 \\
5x-4y+30=0
\end{array}
\right.
\end{eqnarray}$
投稿日：2013.05.21
