問題文全文(内容文)：
1⃣
$(12a^2-6a)\div \displaystyle \frac{2}{3}$
2⃣
$(\displaystyle \frac{2}{3}x^2y^2-\displaystyle \frac{4}{9}xy^2+2xy)\div(-\displaystyle \frac{2}{9}xy)$
3⃣
$(4x^3-6x^2+\displaystyle \frac{8}{5}x)\div(-\displaystyle \frac{4}{5}x)$
4⃣
$(-8a^2b+16ab)\div \displaystyle \frac{4}{5}a$
5⃣
$(4ab^2+5abc+\displaystyle \frac{1}{2})\div(\displaystyle \frac{7b}{5a})$
1⃣
$(12a^2-6a)\div \displaystyle \frac{2}{3}$
2⃣
$(\displaystyle \frac{2}{3}x^2y^2-\displaystyle \frac{4}{9}xy^2+2xy)\div(-\displaystyle \frac{2}{9}xy)$
3⃣
$(4x^3-6x^2+\displaystyle \frac{8}{5}x)\div(-\displaystyle \frac{4}{5}x)$
4⃣
$(-8a^2b+16ab)\div \displaystyle \frac{4}{5}a$
5⃣
$(4ab^2+5abc+\displaystyle \frac{1}{2})\div(\displaystyle \frac{7b}{5a})$
チャプター：
00:00 はじまり
00:35 問題解説前半
04:14 問題解説中盤
06:53 問題解説最後
07:43 まとめ
08:07 問題と解答
単元：
#数学(中学生)#中３数学#式の計算（展開、因数分解）
指導講師：
【楽しい授業動画】あきとんとん
問題文全文(内容文)：
1⃣
$(12a^2-6a)\div \displaystyle \frac{2}{3}$
2⃣
$(\displaystyle \frac{2}{3}x^2y^2-\displaystyle \frac{4}{9}xy^2+2xy)\div(-\displaystyle \frac{2}{9}xy)$
3⃣
$(4x^3-6x^2+\displaystyle \frac{8}{5}x)\div(-\displaystyle \frac{4}{5}x)$
4⃣
$(-8a^2b+16ab)\div \displaystyle \frac{4}{5}a$
5⃣
$(4ab^2+5abc+\displaystyle \frac{1}{2})\div(\displaystyle \frac{7b}{5a})$
1⃣
$(12a^2-6a)\div \displaystyle \frac{2}{3}$
2⃣
$(\displaystyle \frac{2}{3}x^2y^2-\displaystyle \frac{4}{9}xy^2+2xy)\div(-\displaystyle \frac{2}{9}xy)$
3⃣
$(4x^3-6x^2+\displaystyle \frac{8}{5}x)\div(-\displaystyle \frac{4}{5}x)$
4⃣
$(-8a^2b+16ab)\div \displaystyle \frac{4}{5}a$
5⃣
$(4ab^2+5abc+\displaystyle \frac{1}{2})\div(\displaystyle \frac{7b}{5a})$
投稿日：2021.05.09
