問題文全文(内容文)：
2.次の計算をしよう.
$\boxed{1} \quad (-3^2)+5\div \dfrac{1}{2}$
$\boxed{2} \quad (-9)+(-2)$
$boxed{3} \quad (-5)\div \dfrac{6}{7} \times \left(-\dfrac{3}{10}\right)$
$\boxed{4} \quad 6^2\div (-3)$
$\boxed{5} \quad (-2.4)\div (-8)$
$\boxed{6} \quad -3-5$
$\boxed{7} \quad (-2)^4\div 8^2$
$\boxed{8} \quad -2.1-1.3+3$
$\boxed{9} \quad \left(-\dfrac{4}{5}\right)\div \left(-\dfrac{6}{5}\right)\div \left(-\dfrac{8}{9}\right)$
$\boxed{10} \quad 31-(5-14)\times (-2)^2$
2.次の計算をしよう.
$\boxed{1} \quad (-3^2)+5\div \dfrac{1}{2}$
$\boxed{2} \quad (-9)+(-2)$
$boxed{3} \quad (-5)\div \dfrac{6}{7} \times \left(-\dfrac{3}{10}\right)$
$\boxed{4} \quad 6^2\div (-3)$
$\boxed{5} \quad (-2.4)\div (-8)$
$\boxed{6} \quad -3-5$
$\boxed{7} \quad (-2)^4\div 8^2$
$\boxed{8} \quad -2.1-1.3+3$
$\boxed{9} \quad \left(-\dfrac{4}{5}\right)\div \left(-\dfrac{6}{5}\right)\div \left(-\dfrac{8}{9}\right)$
$\boxed{10} \quad 31-(5-14)\times (-2)^2$
単元：
#数学(中学生)#中1数学#正の数・負の数
指導講師：
とある男が授業をしてみた
問題文全文(内容文)：
2.次の計算をしよう.
$\boxed{1} \quad (-3^2)+5\div \dfrac{1}{2}$
$\boxed{2} \quad (-9)+(-2)$
$boxed{3} \quad (-5)\div \dfrac{6}{7} \times \left(-\dfrac{3}{10}\right)$
$\boxed{4} \quad 6^2\div (-3)$
$\boxed{5} \quad (-2.4)\div (-8)$
$\boxed{6} \quad -3-5$
$\boxed{7} \quad (-2)^4\div 8^2$
$\boxed{8} \quad -2.1-1.3+3$
$\boxed{9} \quad \left(-\dfrac{4}{5}\right)\div \left(-\dfrac{6}{5}\right)\div \left(-\dfrac{8}{9}\right)$
$\boxed{10} \quad 31-(5-14)\times (-2)^2$
2.次の計算をしよう.
$\boxed{1} \quad (-3^2)+5\div \dfrac{1}{2}$
$\boxed{2} \quad (-9)+(-2)$
$boxed{3} \quad (-5)\div \dfrac{6}{7} \times \left(-\dfrac{3}{10}\right)$
$\boxed{4} \quad 6^2\div (-3)$
$\boxed{5} \quad (-2.4)\div (-8)$
$\boxed{6} \quad -3-5$
$\boxed{7} \quad (-2)^4\div 8^2$
$\boxed{8} \quad -2.1-1.3+3$
$\boxed{9} \quad \left(-\dfrac{4}{5}\right)\div \left(-\dfrac{6}{5}\right)\div \left(-\dfrac{8}{9}\right)$
$\boxed{10} \quad 31-(5-14)\times (-2)^2$
投稿日：2016.07.14
