問題文全文(内容文)：
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{dx}{dt}=2x+4y ・・・① \\
\displaystyle \frac{dy}{dt}=x-y ・・・②
\end{array}
\right.
\end{eqnarray}$
$x(0)=3,\ y(0=-1)$を満たす解を求めよ。
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{dx}{dt}=2x+4y ・・・① \\
\displaystyle \frac{dy}{dt}=x-y ・・・②
\end{array}
\right.
\end{eqnarray}$
$x(0)=3,\ y(0=-1)$を満たす解を求めよ。
単元：
Warning: usort() expects parameter 1 to be array, bool given in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 102
Warning: Invalid argument supplied for foreach() in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 103
Warning: usort() expects parameter 1 to be array, bool given in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 102
Warning: Invalid argument supplied for foreach() in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 103
指導講師：
ますただ
問題文全文(内容文)：
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{dx}{dt}=2x+4y ・・・① \\
\displaystyle \frac{dy}{dt}=x-y ・・・②
\end{array}
\right.
\end{eqnarray}$
$x(0)=3,\ y(0=-1)$を満たす解を求めよ。
$\begin{eqnarray}
\left\{
\begin{array}{l}
\displaystyle \frac{dx}{dt}=2x+4y ・・・① \\
\displaystyle \frac{dy}{dt}=x-y ・・・②
\end{array}
\right.
\end{eqnarray}$
$x(0)=3,\ y(0=-1)$を満たす解を求めよ。
投稿日：2022.06.18