問題文全文(内容文)：
2⃣ $f(x) = \frac{x}{1+x^2}$
f(α)=f(β) , 0 < α < β のとき$\int_α^β \frac{x}{1+x^2}dx= log_β$を示せ
2⃣ $f(x) = \frac{x}{1+x^2}$
f(α)=f(β) , 0 < α < β のとき$\int_α^β \frac{x}{1+x^2}dx= log_β$を示せ
単元：
Warning: usort() expects parameter 1 to be array, bool given in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 102
Warning: Invalid argument supplied for foreach() in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 103
Warning: usort() expects parameter 1 to be array, bool given in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 102
Warning: Invalid argument supplied for foreach() in /home/kaiketsudb/kaiketsu-db.net/public_html/wp-content/themes/lightning-child-sample/single.php on line 103
指導講師：
ますただ
問題文全文(内容文)：
2⃣ $f(x) = \frac{x}{1+x^2}$
f(α)=f(β) , 0 < α < β のとき$\int_α^β \frac{x}{1+x^2}dx= log_β$を示せ
2⃣ $f(x) = \frac{x}{1+x^2}$
f(α)=f(β) , 0 < α < β のとき$\int_α^β \frac{x}{1+x^2}dx= log_β$を示せ
投稿日：2020.11.08