問題文全文(内容文)：
次の計算を解け.
①$\begin{eqnarray}
\left\{
\begin{array}{l}
0.3x+0.7y=5 \\
0.9x+\dfrac{1}{10}y=-1
\end{array}
\right.
\end{eqnarray}$
②$\begin{eqnarray}
\left\{
\begin{array}{l}
3x-2y-7=0 \\
2(x+2y)=y=-4
\end{array}
\right.
\end{eqnarray}$
③$\begin{eqnarray}
\left\{
\begin{array}{l}
\dfrac{2}{3}x+\dfrac{1}{4}y=3.5 \\
-0.2x+0.5y=2.4
\end{array}
\right.
\end{eqnarray}$
④$\begin{eqnarray}
\left\{
\begin{array}{l}
2(x-y)=-7y \\
\dfrac{4x+y}{6}-\dfrac{x-2y}{2}=-\dfrac{3}{2}
\end{array}
\right.
\end{eqnarray}$
⑤$2x+3y-8=3x+y=-x-2y+1$
次の計算を解け.
①$\begin{eqnarray}
\left\{
\begin{array}{l}
0.3x+0.7y=5 \\
0.9x+\dfrac{1}{10}y=-1
\end{array}
\right.
\end{eqnarray}$
②$\begin{eqnarray}
\left\{
\begin{array}{l}
3x-2y-7=0 \\
2(x+2y)=y=-4
\end{array}
\right.
\end{eqnarray}$
③$\begin{eqnarray}
\left\{
\begin{array}{l}
\dfrac{2}{3}x+\dfrac{1}{4}y=3.5 \\
-0.2x+0.5y=2.4
\end{array}
\right.
\end{eqnarray}$
④$\begin{eqnarray}
\left\{
\begin{array}{l}
2(x-y)=-7y \\
\dfrac{4x+y}{6}-\dfrac{x-2y}{2}=-\dfrac{3}{2}
\end{array}
\right.
\end{eqnarray}$
⑤$2x+3y-8=3x+y=-x-2y+1$
単元：
#数学(中学生)#中2数学#連立方程式
指導講師：
とある男が授業をしてみた
問題文全文(内容文)：
次の計算を解け.
①$\begin{eqnarray}
\left\{
\begin{array}{l}
0.3x+0.7y=5 \\
0.9x+\dfrac{1}{10}y=-1
\end{array}
\right.
\end{eqnarray}$
②$\begin{eqnarray}
\left\{
\begin{array}{l}
3x-2y-7=0 \\
2(x+2y)=y=-4
\end{array}
\right.
\end{eqnarray}$
③$\begin{eqnarray}
\left\{
\begin{array}{l}
\dfrac{2}{3}x+\dfrac{1}{4}y=3.5 \\
-0.2x+0.5y=2.4
\end{array}
\right.
\end{eqnarray}$
④$\begin{eqnarray}
\left\{
\begin{array}{l}
2(x-y)=-7y \\
\dfrac{4x+y}{6}-\dfrac{x-2y}{2}=-\dfrac{3}{2}
\end{array}
\right.
\end{eqnarray}$
⑤$2x+3y-8=3x+y=-x-2y+1$
次の計算を解け.
①$\begin{eqnarray}
\left\{
\begin{array}{l}
0.3x+0.7y=5 \\
0.9x+\dfrac{1}{10}y=-1
\end{array}
\right.
\end{eqnarray}$
②$\begin{eqnarray}
\left\{
\begin{array}{l}
3x-2y-7=0 \\
2(x+2y)=y=-4
\end{array}
\right.
\end{eqnarray}$
③$\begin{eqnarray}
\left\{
\begin{array}{l}
\dfrac{2}{3}x+\dfrac{1}{4}y=3.5 \\
-0.2x+0.5y=2.4
\end{array}
\right.
\end{eqnarray}$
④$\begin{eqnarray}
\left\{
\begin{array}{l}
2(x-y)=-7y \\
\dfrac{4x+y}{6}-\dfrac{x-2y}{2}=-\dfrac{3}{2}
\end{array}
\right.
\end{eqnarray}$
⑤$2x+3y-8=3x+y=-x-2y+1$
投稿日：2017.06.08
