問題文全文(内容文):
$\displaystyle \int (log\ x+\displaystyle \frac{1}{x})log(x+1) dx$
$\displaystyle \int (log\ x+\displaystyle \frac{1}{x})log(x+1) dx$
単元:
#積分とその応用#不定積分#数学(高校生)#数Ⅲ
指導講師:
ますただ
問題文全文(内容文):
$\displaystyle \int (log\ x+\displaystyle \frac{1}{x})log(x+1) dx$
$\displaystyle \int (log\ x+\displaystyle \frac{1}{x})log(x+1) dx$
投稿日:2023.06.22