問題文全文(内容文):
$\displaystyle \prod_{n=1}^\infty cos(\frac x{2^n}) = cos\frac x{2}cos\frac x{4} cos\frac x{8} \cdots cos\frac x{2^n} = \frac {sinx}x $
$\displaystyle \prod_{n=1}^\infty cos(\frac x{2^n}) = cos\frac x{2}cos\frac x{4} cos\frac x{8} \cdots cos\frac x{2^n} = \frac {sinx}x $
単元:
#関数と極限#関数の極限#数学(高校生)#数Ⅲ
指導講師:
鈴木貫太郎
問題文全文(内容文):
$\displaystyle \prod_{n=1}^\infty cos(\frac x{2^n}) = cos\frac x{2}cos\frac x{4} cos\frac x{8} \cdots cos\frac x{2^n} = \frac {sinx}x $
$\displaystyle \prod_{n=1}^\infty cos(\frac x{2^n}) = cos\frac x{2}cos\frac x{4} cos\frac x{8} \cdots cos\frac x{2^n} = \frac {sinx}x $
投稿日:2022.12.16