問題文全文(内容文)：
(1) $\displaystyle \int\dfrac{dx}{x(x^2-1)}$
(2) $\displaystyle \int\dfrac{x}{x^3(x+2)}dx$
(3) $\displaystyle \int\dfrac{dx}{x(x^2+1)}$
(4) $\displaystyle \int\dfrac{x^2+1}{x^4-5x^2+4}dx$
(5) $\displaystyle \int\dfrac{3x+2}{x(x+1)^3}dx$
(6) $\displaystyle \int\dfrac{x^4}{x^3-3x+2}dx$
(1) $\displaystyle \int\dfrac{dx}{x(x^2-1)}$
(2) $\displaystyle \int\dfrac{x}{x^3(x+2)}dx$
(3) $\displaystyle \int\dfrac{dx}{x(x^2+1)}$
(4) $\displaystyle \int\dfrac{x^2+1}{x^4-5x^2+4}dx$
(5) $\displaystyle \int\dfrac{3x+2}{x(x+1)^3}dx$
(6) $\displaystyle \int\dfrac{x^4}{x^3-3x+2}dx$
単元：
#積分とその応用#不定積分#数学(高校生)#数Ⅲ
教材：
#4S数学#4S数学ⅢのB問題解説#中高教材#積分法の応用
指導講師：
理数個別チャンネル
問題文全文(内容文)：
(1) $\displaystyle \int\dfrac{dx}{x(x^2-1)}$
(2) $\displaystyle \int\dfrac{x}{x^3(x+2)}dx$
(3) $\displaystyle \int\dfrac{dx}{x(x^2+1)}$
(4) $\displaystyle \int\dfrac{x^2+1}{x^4-5x^2+4}dx$
(5) $\displaystyle \int\dfrac{3x+2}{x(x+1)^3}dx$
(6) $\displaystyle \int\dfrac{x^4}{x^3-3x+2}dx$
(1) $\displaystyle \int\dfrac{dx}{x(x^2-1)}$
(2) $\displaystyle \int\dfrac{x}{x^3(x+2)}dx$
(3) $\displaystyle \int\dfrac{dx}{x(x^2+1)}$
(4) $\displaystyle \int\dfrac{x^2+1}{x^4-5x^2+4}dx$
(5) $\displaystyle \int\dfrac{3x+2}{x(x+1)^3}dx$
(6) $\displaystyle \int\dfrac{x^4}{x^3-3x+2}dx$
投稿日：2026.08.16
